9=-3(1-x)+2(x+1)

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Solution for 9=-3(1-x)+2(x+1) equation: 



9=-3(1-x)+2(x+1)

We move all terms to the left:

9-(-3(1-x)+2(x+1))=0

We add all the numbers together, and all the variables

-(-3(-1x+1)+2(x+1))+9=0



We calculate terms in parentheses: -(-3(-1x+1)+2(x+1)), so:

-3(-1x+1)+2(x+1)

We multiply parentheses

3x+2x-3+2

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)



We get rid of parentheses

-5x+1+9=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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