7x=5(3-2x)+18

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Solution for 7x=5(3-2x)+18 equation: 



7x=5(3-2x)+18

We move all terms to the left:

7x-(5(3-2x)+18)=0

We add all the numbers together, and all the variables

7x-(5(-2x+3)+18)=0



We calculate terms in parentheses: -(5(-2x+3)+18), so:

5(-2x+3)+18

We multiply parentheses

-10x+15+18

We add all the numbers together, and all the variables

-10x+33

Back to the equation:

-(-10x+33)



We get rid of parentheses

7x+10x-33=0

We add all the numbers together, and all the variables

17x-33=0

We move all terms containing x to the left, all other terms to the right

17x=33

x=33/17

x=1+16/17

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