4a-11=3(a+1)+15a+1

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Solution for 4a-11=3(a+1)+15a+1 equation: 



4a-11=3(a+1)+15a+1

We move all terms to the left:

4a-11-(3(a+1)+15a+1)=0



We calculate terms in parentheses: -(3(a+1)+15a+1), so:

3(a+1)+15a+1

We add all the numbers together, and all the variables

15a+3(a+1)+1

We multiply parentheses

15a+3a+3+1

We add all the numbers together, and all the variables

18a+4

Back to the equation:

-(18a+4)



We get rid of parentheses

4a-18a-4-11=0

We add all the numbers together, and all the variables

-14a-15=0

We move all terms containing a to the left, all other terms to the right

-14a=15

a=15/-14

a=-1+1/14

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