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7x=4x^2-2
We move all terms to the left:
7x-(4x^2-2)=0
We get rid of parentheses
-4x^2+7x+2=0
a = -4; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·(-4)·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-9}{2*-4}=\frac{-16}{-8} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+9}{2*-4}=\frac{2}{-8} =-1/4 $
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