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(3x-26)=(2x+36)
We move all terms to the left:
(3x-26)-((2x+36))=0
We get rid of parentheses
3x-((2x+36))-26=0
We calculate terms in parentheses: -((2x+36)), so:We get rid of parentheses
(2x+36)
We get rid of parentheses
2x+36
Back to the equation:
-(2x+36)
3x-2x-36-26=0
We add all the numbers together, and all the variables
x-62=0
We move all terms containing x to the left, all other terms to the right
x=62
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