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7x^2=360
We move all terms to the left:
7x^2-(360)=0
a = 7; b = 0; c = -360;
Δ = b2-4ac
Δ = 02-4·7·(-360)
Δ = 10080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10080}=\sqrt{144*70}=\sqrt{144}*\sqrt{70}=12\sqrt{70}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{70}}{2*7}=\frac{0-12\sqrt{70}}{14} =-\frac{12\sqrt{70}}{14} =-\frac{6\sqrt{70}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{70}}{2*7}=\frac{0+12\sqrt{70}}{14} =\frac{12\sqrt{70}}{14} =\frac{6\sqrt{70}}{7} $
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