6y+3(2y-4)=12

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Solution for 6y+3(2y-4)=12 equation: 



6y+3(2y-4)=12

We move all terms to the left:

6y+3(2y-4)-(12)=0

We multiply parentheses

6y+6y-12-12=0

We add all the numbers together, and all the variables

12y-24=0

We move all terms containing y to the left, all other terms to the right

12y=24

y=24/12

y=2

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