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7x^2+35x+42=0
a = 7; b = 35; c = +42;
Δ = b2-4ac
Δ = 352-4·7·42
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-7}{2*7}=\frac{-42}{14} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+7}{2*7}=\frac{-28}{14} =-2 $
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