5(2x+3)=12x+3-2(3x+2)

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Solution for 5(2x+3)=12x+3-2(3x+2) equation: 



5(2x+3)=12x+3-2(3x+2)

We move all terms to the left:

5(2x+3)-(12x+3-2(3x+2))=0

We multiply parentheses

10x-(12x+3-2(3x+2))+15=0



We calculate terms in parentheses: -(12x+3-2(3x+2)), so:

12x+3-2(3x+2)

determiningTheFunctionDomain
12x-2(3x+2)+3

We multiply parentheses

12x-6x-4+3

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

10x-6x+1+15=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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