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7x-5(x-2)=4-2(x-5)
We move all terms to the left:
7x-5(x-2)-(4-2(x-5))=0
We multiply parentheses
7x-5x-(4-2(x-5))+10=0
We calculate terms in parentheses: -(4-2(x-5)), so:We add all the numbers together, and all the variables
4-2(x-5)
determiningTheFunctionDomain -2(x-5)+4
We multiply parentheses
-2x+10+4
We add all the numbers together, and all the variables
-2x+14
Back to the equation:
-(-2x+14)
2x-(-2x+14)+10=0
We get rid of parentheses
2x+2x-14+10=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1
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