8(y+3)=6y+40

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Solution for 8(y+3)=6y+40 equation:



8(y+3)=6y+40
We move all terms to the left:
8(y+3)-(6y+40)=0
We multiply parentheses
8y-(6y+40)+24=0
We get rid of parentheses
8y-6y-40+24=0
We add all the numbers together, and all the variables
2y-16=0
We move all terms containing y to the left, all other terms to the right
2y=16
y=16/2
y=8

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