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7x-5(2x-4)-8=15-(3-x-4x
We move all terms to the left:
7x-5(2x-4)-8-(15-(3-x-4x)=0
We add all the numbers together, and all the variables
7x-5(2x-4)-(15-(-5x+3)-8=0
We multiply parentheses
7x-10x-(15-(-5x+3)-8+20=0
We add all the numbers together, and all the variables
-3x-(15-(-5x+3)-8+20=0
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