(-8y+16)+(8y+12)=2(3y+11)

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Solution for (-8y+16)+(8y+12)=2(3y+11) equation: 



(-8y+16)+(8y+12)=2(3y+11)

We move all terms to the left:

(-8y+16)+(8y+12)-(2(3y+11))=0

We get rid of parentheses

-8y+8y-(2(3y+11))+16+12=0



We calculate terms in parentheses: -(2(3y+11)), so:

2(3y+11)

We multiply parentheses

6y+22

Back to the equation:

-(6y+22)



We add all the numbers together, and all the variables

-(6y+22)+28=0

We get rid of parentheses

-6y-22+28=0

We add all the numbers together, and all the variables

-6y+6=0

We move all terms containing y to the left, all other terms to the right

-6y=-6

y=-6/-6

y=1

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