7x-4(x-4)+20=8

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Solution for 7x-4(x-4)+20=8 equation: 



7x-4(x-4)+20=8

We move all terms to the left:

7x-4(x-4)+20-(8)=0

We add all the numbers together, and all the variables

7x-4(x-4)+12=0

We multiply parentheses

7x-4x+16+12=0

We add all the numbers together, and all the variables

3x+28=0

We move all terms containing x to the left, all other terms to the right

3x=-28

x=-28/3

x=-9+1/3

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