X2+13x-240=0

Solution for X2+13x-240=0 equation:

X2+13X-240=0

We add all the numbers together, and all the variables

X^2+13X-240=0

a = 1; b = 13; c = -240;
Δ = b2-4ac
Δ = 132-4·1·(-240)
Δ = 1129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{1129}}{2*1}=\frac{-13-\sqrt{1129}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{1129}}{2*1}=\frac{-13+\sqrt{1129}}{2}
$