7x-4(x+3)=2(x-13)

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Solution for 7x-4(x+3)=2(x-13) equation: 



7x-4(x+3)=2(x-13)

We move all terms to the left:

7x-4(x+3)-(2(x-13))=0

We multiply parentheses

7x-4x-(2(x-13))-12=0



We calculate terms in parentheses: -(2(x-13)), so:

2(x-13)

We multiply parentheses

2x-26

Back to the equation:

-(2x-26)



We add all the numbers together, and all the variables

3x-(2x-26)-12=0

We get rid of parentheses

3x-2x+26-12=0

We add all the numbers together, and all the variables

x+14=0

We move all terms containing x to the left, all other terms to the right

x=-14

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