7x-4(3-2x)=48

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Solution for 7x-4(3-2x)=48 equation: 



7x-4(3-2x)=48

We move all terms to the left:

7x-4(3-2x)-(48)=0

We add all the numbers together, and all the variables

7x-4(-2x+3)-48=0

We multiply parentheses

7x+8x-12-48=0

We add all the numbers together, and all the variables

15x-60=0

We move all terms containing x to the left, all other terms to the right

15x=60

x=60/15

x=4

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