7x-3(3-2x)=3(x-5)-44

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Solution for 7x-3(3-2x)=3(x-5)-44 equation: 



7x-3(3-2x)=3(x-5)-44

We move all terms to the left:

7x-3(3-2x)-(3(x-5)-44)=0

We add all the numbers together, and all the variables

7x-3(-2x+3)-(3(x-5)-44)=0

We multiply parentheses

7x+6x-(3(x-5)-44)-9=0



We calculate terms in parentheses: -(3(x-5)-44), so:

3(x-5)-44

We multiply parentheses

3x-15-44

We add all the numbers together, and all the variables

3x-59

Back to the equation:

-(3x-59)



We add all the numbers together, and all the variables

13x-(3x-59)-9=0

We get rid of parentheses

13x-3x+59-9=0

We add all the numbers together, and all the variables

10x+50=0

We move all terms containing x to the left, all other terms to the right

10x=-50

x=-50/10

x=-5

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