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7x-2x+12=2(x-2)+6
We move all terms to the left:
7x-2x+12-(2(x-2)+6)=0
We add all the numbers together, and all the variables
5x-(2(x-2)+6)+12=0
We calculate terms in parentheses: -(2(x-2)+6), so:We get rid of parentheses
2(x-2)+6
We multiply parentheses
2x-4+6
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
5x-2x-2+12=0
We add all the numbers together, and all the variables
3x+10=0
We move all terms containing x to the left, all other terms to the right
3x=-10
x=-10/3
x=-3+1/3
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