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4/3(-9x+12)-x=13x+5
We move all terms to the left:
4/3(-9x+12)-x-(13x+5)=0
Domain of the equation: 3(-9x+12)!=0We add all the numbers together, and all the variables
x∈R
-1x+4/3(-9x+12)-(13x+5)=0
We get rid of parentheses
-1x+4/3(-9x+12)-13x-5=0
We multiply all the terms by the denominator
-1x*3(-9x+12)-13x*3(-9x+12)-5*3(-9x+12)+4=0
Wy multiply elements
-3x^2(--39x^2(--15x(-+4=0
We use the square of the difference formula
-3x^2(+39x^2(+15x(-4=0
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