(15b-4)-7(2b+2)=-6

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Solution for (15b-4)-7(2b+2)=-6 equation: 



(15b-4)-7(2b+2)=-6

We move all terms to the left:

(15b-4)-7(2b+2)-(-6)=0

We add all the numbers together, and all the variables

(15b-4)-7(2b+2)+6=0

We multiply parentheses

(15b-4)-14b-14+6=0

We get rid of parentheses

15b-14b-4-14+6=0

We add all the numbers together, and all the variables

b-12=0

We move all terms containing b to the left, all other terms to the right

b=12

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