7x-2(x-5)=3(x+2)+2(x+2)

Solution for 7x-2(x-5)=3(x+2)+2(x+2) equation:

7x-2(x-5)=3(x+2)+2(x+2)

We move all terms to the left:

7x-2(x-5)-(3(x+2)+2(x+2))=0

We multiply parentheses

7x-2x-(3(x+2)+2(x+2))+10=0


We calculate terms in parentheses: -(3(x+2)+2(x+2)), so:

3(x+2)+2(x+2)

We multiply parentheses

3x+2x+6+4

We add all the numbers together, and all the variables

5x+10

Back to the equation:

-(5x+10)


We add all the numbers together, and all the variables

5x-(5x+10)+10=0

We get rid of parentheses

5x-5x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0