2(4x+2)-8=4(x+3)=

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Solution for 2(4x+2)-8=4(x+3)= equation: 



2(4x+2)-8=4(x+3)=

We move all terms to the left:

2(4x+2)-8-(4(x+3))=0

We multiply parentheses

8x-(4(x+3))+4-8=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

8x-(4x+12)-4=0

We get rid of parentheses

8x-4x-12-4=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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