7x-2(3x-2)+5=3(x-4)

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Solution for 7x-2(3x-2)+5=3(x-4) equation: 



7x-2(3x-2)+5=3(x-4)

We move all terms to the left:

7x-2(3x-2)+5-(3(x-4))=0

We multiply parentheses

7x-6x-(3(x-4))+4+5=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

x-(3x-12)+9=0

We get rid of parentheses

x-3x+12+9=0

We add all the numbers together, and all the variables

-2x+21=0

We move all terms containing x to the left, all other terms to the right

-2x=-21

x=-21/-2

x=10+1/2

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