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(X-3)5X+1=0
We multiply parentheses
5X^2-15X+1=0
a = 5; b = -15; c = +1;
Δ = b2-4ac
Δ = -152-4·5·1
Δ = 205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{205}}{2*5}=\frac{15-\sqrt{205}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{205}}{2*5}=\frac{15+\sqrt{205}}{10} $
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