7x-2(3x-1)=4x-(3-x)-19

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Solution for 7x-2(3x-1)=4x-(3-x)-19 equation: 



7x-2(3x-1)=4x-(3-x)-19

We move all terms to the left:

7x-2(3x-1)-(4x-(3-x)-19)=0

We add all the numbers together, and all the variables

7x-2(3x-1)-(4x-(-1x+3)-19)=0

We multiply parentheses

7x-6x-(4x-(-1x+3)-19)+2=0



We calculate terms in parentheses: -(4x-(-1x+3)-19), so:

4x-(-1x+3)-19

We get rid of parentheses

4x+1x-3-19

We add all the numbers together, and all the variables

5x-22

Back to the equation:

-(5x-22)



We add all the numbers together, and all the variables

x-(5x-22)+2=0

We get rid of parentheses

x-5x+22+2=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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