6(x-3)+10=2(4x-5

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Solution for 6(x-3)+10=2(4x-5 equation: 



6(x-3)+10=2(4x-5

We move all terms to the left:

6(x-3)+10-(2(4x-5)=0

We multiply parentheses

6x-(2(4x-5)+10-18=0

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