7x-2(3-x)=4(x+1)

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Solution for 7x-2(3-x)=4(x+1) equation: 



7x-2(3-x)=4(x+1)

We move all terms to the left:

7x-2(3-x)-(4(x+1))=0

We add all the numbers together, and all the variables

7x-2(-1x+3)-(4(x+1))=0

We multiply parentheses

7x+2x-(4(x+1))-6=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

9x-(4x+4)-6=0

We get rid of parentheses

9x-4x-4-6=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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