7x-1/2(2x-8)=-5/4(x+8)

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Solution for 7x-1/2(2x-8)=-5/4(x+8) equation: 



7x-1/2(2x-8)=-5/4(x+8)

We move all terms to the left:

7x-1/2(2x-8)-(-5/4(x+8))=0



Domain of the equation: 2(2x-8)!=0

x∈R





Domain of the equation: 4(x+8))!=0

x∈R



We calculate fractions


7x+(-4xx/(2(2x-8)*4(x+8)))+(-(-10x2)/(2(2x-8)*4(x+8)))=0



We calculate terms in parentheses: +(-4xx/(2(2x-8)*4(x+8))), so:

-4xx/(2(2x-8)*4(x+8))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)





We calculate terms in parentheses: +(-(-10x2)/(2(2x-8)*4(x+8))), so:

-(-10x2)/(2(2x-8)*4(x+8))

We add all the numbers together, and all the variables

-(-10x^2)/(2(2x-8)*4(x+8))

We multiply all the terms by the denominator


-(-10x^2)

We get rid of parentheses

10x^2

Back to the equation:

+(10x^2)



determiningTheFunctionDomain
10x^2+7x+(-4xx)=0

We get rid of parentheses

10x^2+7x-4xx=0

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