(6x-4)+(8x-4)+(9x-4)=80

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Solution for (6x-4)+(8x-4)+(9x-4)=80 equation: 



(6x-4)+(8x-4)+(9x-4)=80

We move all terms to the left:

(6x-4)+(8x-4)+(9x-4)-(80)=0

We get rid of parentheses

6x+8x+9x-4-4-4-80=0

We add all the numbers together, and all the variables

23x-92=0

We move all terms containing x to the left, all other terms to the right

23x=92

x=92/23

x=4

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