4n+6-2n=(n+3)-11

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Solution for 4n+6-2n=(n+3)-11 equation: 



4n+6-2n=(n+3)-11

We move all terms to the left:

4n+6-2n-((n+3)-11)=0

We add all the numbers together, and all the variables

2n-((n+3)-11)+6=0



We calculate terms in parentheses: -((n+3)-11), so:

(n+3)-11

We get rid of parentheses

n+3-11

We add all the numbers together, and all the variables

n-8

Back to the equation:

-(n-8)



We get rid of parentheses

2n-n+8+6=0

We add all the numbers together, and all the variables

n+14=0

We move all terms containing n to the left, all other terms to the right

n=-14

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