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7x-(x+3)=3(x+1)
We move all terms to the left:
7x-(x+3)-(3(x+1))=0
We get rid of parentheses
7x-x-(3(x+1))-3=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
6x-(3x+3)-3=0
We get rid of parentheses
6x-3x-3-3=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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