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3(x-2)=5-2(3-2x)
We move all terms to the left:
3(x-2)-(5-2(3-2x))=0
We add all the numbers together, and all the variables
3(x-2)-(5-2(-2x+3))=0
We multiply parentheses
3x-(5-2(-2x+3))-6=0
We calculate terms in parentheses: -(5-2(-2x+3)), so:We get rid of parentheses
5-2(-2x+3)
determiningTheFunctionDomain -2(-2x+3)+5
We multiply parentheses
4x-6+5
We add all the numbers together, and all the variables
4x-1
Back to the equation:
-(4x-1)
3x-4x+1-6=0
We add all the numbers together, and all the variables
-1x-5=0
We move all terms containing x to the left, all other terms to the right
-x=5
x=5/-1
x=-5
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