7x-(2x-2)-8=3(4x-9)+77x-(2x-2)-8=3(4x-9)+7

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Solution for 7x-(2x-2)-8=3(4x-9)+77x-(2x-2)-8=3(4x-9)+7 equation: 



7x-(2x-2)-8=3(4x-9)+77x-(2x-2)-8=3(4x-9)+7

We move all terms to the left:

7x-(2x-2)-8-(3(4x-9)+77x-(2x-2)-8)=0

We get rid of parentheses

7x-2x-(3(4x-9)+77x-(2x-2)-8)+2-8=0



We calculate terms in parentheses: -(3(4x-9)+77x-(2x-2)-8), so:

3(4x-9)+77x-(2x-2)-8

We add all the numbers together, and all the variables

77x+3(4x-9)-(2x-2)-8

We multiply parentheses

77x+12x-(2x-2)-27-8

We get rid of parentheses

77x+12x-2x+2-27-8

We add all the numbers together, and all the variables

87x-33

Back to the equation:

-(87x-33)



We add all the numbers together, and all the variables

5x-(87x-33)-6=0

We get rid of parentheses

5x-87x+33-6=0

We add all the numbers together, and all the variables

-82x+27=0

We move all terms containing x to the left, all other terms to the right

-82x=-27

x=-27/-82

x=27/82

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