-39=3(y-4)-6y

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Solution for -39=3(y-4)-6y equation: 



-39=3(y-4)-6y

We move all terms to the left:

-39-(3(y-4)-6y)=0



We calculate terms in parentheses: -(3(y-4)-6y), so:

3(y-4)-6y

We add all the numbers together, and all the variables

-6y+3(y-4)

We multiply parentheses

-6y+3y-12

We add all the numbers together, and all the variables

-3y-12

Back to the equation:

-(-3y-12)



We get rid of parentheses

3y+12-39=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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