7x+5=3(2x+2)+(x-1)

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Solution for 7x+5=3(2x+2)+(x-1) equation: 



7x+5=3(2x+2)+(x-1)

We move all terms to the left:

7x+5-(3(2x+2)+(x-1))=0



We calculate terms in parentheses: -(3(2x+2)+(x-1)), so:

3(2x+2)+(x-1)

We multiply parentheses

6x+(x-1)+6

We get rid of parentheses

6x+x-1+6

We add all the numbers together, and all the variables

7x+5

Back to the equation:

-(7x+5)



We get rid of parentheses

7x-7x-5+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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