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3/2(6h-12)+5=2/5(10h-6)
We move all terms to the left:
3/2(6h-12)+5-(2/5(10h-6))=0
Domain of the equation: 2(6h-12)!=0
h∈R
Domain of the equation: 5(10h-6))!=0We calculate fractions
h∈R
(15h1/(2(6h-12)*5(10h-6)))+(-4h6/(2(6h-12)*5(10h-6)))+5=0
We calculate terms in parentheses: +(15h1/(2(6h-12)*5(10h-6))), so:
15h1/(2(6h-12)*5(10h-6))
We multiply all the terms by the denominator
15h1
We add all the numbers together, and all the variables
15h
Back to the equation:
+(15h)
We calculate terms in parentheses: +(-4h6/(2(6h-12)*5(10h-6))), so:
-4h6/(2(6h-12)*5(10h-6))
We multiply all the terms by the denominator
-4h6
We add all the numbers together, and all the variables
-4h^6
We do not support ehpression: h^6
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