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7x+5(-7+x)=3(x-3)-4x
We move all terms to the left:
7x+5(-7+x)-(3(x-3)-4x)=0
We add all the numbers together, and all the variables
7x+5(x-7)-(3(x-3)-4x)=0
We multiply parentheses
7x+5x-(3(x-3)-4x)-35=0
We calculate terms in parentheses: -(3(x-3)-4x), so:We add all the numbers together, and all the variables
3(x-3)-4x
We add all the numbers together, and all the variables
-4x+3(x-3)
We multiply parentheses
-4x+3x-9
We add all the numbers together, and all the variables
-1x-9
Back to the equation:
-(-1x-9)
12x-(-1x-9)-35=0
We get rid of parentheses
12x+1x+9-35=0
We add all the numbers together, and all the variables
13x-26=0
We move all terms containing x to the left, all other terms to the right
13x=26
x=26/13
x=2
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