-3(1+h)=1/3(3-12h)

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Solution for -3(1+h)=1/3(3-12h) equation: 



-3(1+h)=1/3(3-12h)

We move all terms to the left:

-3(1+h)-(1/3(3-12h))=0



Domain of the equation: 3(3-12h))!=0

h∈R



We add all the numbers together, and all the variables

-3(h+1)-(1/3(-12h+3))=0

We multiply parentheses

-3h-(1/3(-12h+3))-3=0

We multiply all the terms by the denominator


-3h*3(-12h+3))-(1-3*3(-12h+3))=0

Wy multiply elements

-9h^2(--9h(-=0

We use the square of the difference formula

-9h^2(+9h(-=0

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