7x+3x-10=16+4(3x-2)

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Solution for 7x+3x-10=16+4(3x-2) equation: 



7x+3x-10=16+4(3x-2)

We move all terms to the left:

7x+3x-10-(16+4(3x-2))=0

We add all the numbers together, and all the variables

10x-(16+4(3x-2))-10=0



We calculate terms in parentheses: -(16+4(3x-2)), so:

16+4(3x-2)

determiningTheFunctionDomain
4(3x-2)+16

We multiply parentheses

12x-8+16

We add all the numbers together, and all the variables

12x+8

Back to the equation:

-(12x+8)



We get rid of parentheses

10x-12x-8-10=0

We add all the numbers together, and all the variables

-2x-18=0

We move all terms containing x to the left, all other terms to the right

-2x=18

x=18/-2

x=-9

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