9(-15+b)=6(b-21)

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Solution for 9(-15+b)=6(b-21) equation: 



9(-15+b)=6(b-21)

We move all terms to the left:

9(-15+b)-(6(b-21))=0

We add all the numbers together, and all the variables

9(b-15)-(6(b-21))=0

We multiply parentheses

9b-(6(b-21))-135=0



We calculate terms in parentheses: -(6(b-21)), so:

6(b-21)

We multiply parentheses

6b-126

Back to the equation:

-(6b-126)



We get rid of parentheses

9b-6b+126-135=0

We add all the numbers together, and all the variables

3b-9=0

We move all terms containing b to the left, all other terms to the right

3b=9

b=9/3

b=3

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