7x+2(3x-10)=136

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Solution for 7x+2(3x-10)=136 equation: 



7x+2(3x-10)=136

We move all terms to the left:

7x+2(3x-10)-(136)=0

We multiply parentheses

7x+6x-20-136=0

We add all the numbers together, and all the variables

13x-156=0

We move all terms containing x to the left, all other terms to the right

13x=156

x=156/13

x=12

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