7x+4(2x-3)=78

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Solution for 7x+4(2x-3)=78 equation: 



7x+4(2x-3)=78

We move all terms to the left:

7x+4(2x-3)-(78)=0

We multiply parentheses

7x+8x-12-78=0

We add all the numbers together, and all the variables

15x-90=0

We move all terms containing x to the left, all other terms to the right

15x=90

x=90/15

x=6

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