7x+2(1+3x)=-8(-2x-7)+6x

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Solution for 7x+2(1+3x)=-8(-2x-7)+6x equation: 



7x+2(1+3x)=-8(-2x-7)+6x

We move all terms to the left:

7x+2(1+3x)-(-8(-2x-7)+6x)=0

We add all the numbers together, and all the variables

7x+2(3x+1)-(-8(-2x-7)+6x)=0

We multiply parentheses

7x+6x-(-8(-2x-7)+6x)+2=0



We calculate terms in parentheses: -(-8(-2x-7)+6x), so:

-8(-2x-7)+6x

We add all the numbers together, and all the variables

6x-8(-2x-7)

We multiply parentheses

6x+16x+56

We add all the numbers together, and all the variables

22x+56

Back to the equation:

-(22x+56)



We add all the numbers together, and all the variables

13x-(22x+56)+2=0

We get rid of parentheses

13x-22x-56+2=0

We add all the numbers together, and all the variables

-9x-54=0

We move all terms containing x to the left, all other terms to the right

-9x=54

x=54/-9

x=-6

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