4(7+4b)=4(b+1)

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Solution for 4(7+4b)=4(b+1) equation: 



4(7+4b)=4(b+1)

We move all terms to the left:

4(7+4b)-(4(b+1))=0

We add all the numbers together, and all the variables

4(4b+7)-(4(b+1))=0

We multiply parentheses

16b-(4(b+1))+28=0



We calculate terms in parentheses: -(4(b+1)), so:

4(b+1)

We multiply parentheses

4b+4

Back to the equation:

-(4b+4)



We get rid of parentheses

16b-4b-4+28=0

We add all the numbers together, and all the variables

12b+24=0

We move all terms containing b to the left, all other terms to the right

12b=-24

b=-24/12

b=-2

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