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7x+10=-2x(x-5)
We move all terms to the left:
7x+10-(-2x(x-5))=0
We calculate terms in parentheses: -(-2x(x-5)), so:We get rid of parentheses
-2x(x-5)
We multiply parentheses
-2x^2+10x
Back to the equation:
-(-2x^2+10x)
2x^2-10x+7x+10=0
We add all the numbers together, and all the variables
2x^2-3x+10=0
a = 2; b = -3; c = +10;
Δ = b2-4ac
Δ = -32-4·2·10
Δ = -71
Delta is less than zero, so there is no solution for the equation
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