-14+3(y+10)=7(2y+4)+y

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Solution for -14+3(y+10)=7(2y+4)+y equation: 



-14+3(y+10)=7(2y+4)+y

We move all terms to the left:

-14+3(y+10)-(7(2y+4)+y)=0

We multiply parentheses

3y-(7(2y+4)+y)+30-14=0



We calculate terms in parentheses: -(7(2y+4)+y), so:

7(2y+4)+y

We add all the numbers together, and all the variables

y+7(2y+4)

We multiply parentheses

y+14y+28

We add all the numbers together, and all the variables

15y+28

Back to the equation:

-(15y+28)



We add all the numbers together, and all the variables

3y-(15y+28)+16=0

We get rid of parentheses

3y-15y-28+16=0

We add all the numbers together, and all the variables

-12y-12=0

We move all terms containing y to the left, all other terms to the right

-12y=12

y=12/-12

y=-1

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