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7x+1/5x+2=1/x+3
We move all terms to the left:
7x+1/5x+2-(1/x+3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x+3)!=0We get rid of parentheses
x∈R
7x+1/5x-1/x-3+2=0
We calculate fractions
7x+x/5x^2+(-5x)/5x^2-3+2=0
We add all the numbers together, and all the variables
7x+x/5x^2+(-5x)/5x^2-1=0
We multiply all the terms by the denominator
7x*5x^2+x+(-5x)-1*5x^2=0
We add all the numbers together, and all the variables
x+7x*5x^2+(-5x)-1*5x^2=0
Wy multiply elements
35x^3-5x^2+x+(-5x)=0
We get rid of parentheses
35x^3-5x^2+x-5x=0
We do not support expression: x^3
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