(5x+50)=(3x+7)+67

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Solution for (5x+50)=(3x+7)+67 equation: 



(5x+50)=(3x+7)+67

We move all terms to the left:

(5x+50)-((3x+7)+67)=0

We get rid of parentheses

5x-((3x+7)+67)+50=0



We calculate terms in parentheses: -((3x+7)+67), so:

(3x+7)+67

We get rid of parentheses

3x+7+67

We add all the numbers together, and all the variables

3x+74

Back to the equation:

-(3x+74)



We get rid of parentheses

5x-3x-74+50=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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