7v+32=-3(4v+8)-2v

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Solution for 7v+32=-3(4v+8)-2v equation: 



7v+32=-3(4v+8)-2v

We move all terms to the left:

7v+32-(-3(4v+8)-2v)=0



We calculate terms in parentheses: -(-3(4v+8)-2v), so:

-3(4v+8)-2v

We add all the numbers together, and all the variables

-2v-3(4v+8)

We multiply parentheses

-2v-12v-24

We add all the numbers together, and all the variables

-14v-24

Back to the equation:

-(-14v-24)



We get rid of parentheses

7v+14v+24+32=0

We add all the numbers together, and all the variables

21v+56=0

We move all terms containing v to the left, all other terms to the right

21v=-56

v=-56/21

v=-2+2/3

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